3.17.31 \(\int \frac {(2+3 x)^7 (3+5 x)}{(1-2 x)^3} \, dx\) [1631]

3.17.31.1 Optimal result

Integrand size = 20, antiderivative size = 73 \[ \int \frac {(2+3 x)^7 (3+5 x)}{(1-2 x)^3} \, dx=\frac {9058973}{1024 (1-2 x)^2}-\frac {15647317}{256 (1-2 x)}-\frac {24960933 x}{256}-\frac {10989621 x^2}{256}-\frac {631611 x^3}{32}-\frac {235467 x^4}{32}-\frac {147987 x^5}{80}-\frac {3645 x^6}{16}-\frac {23647449}{256} \log (1-2 x) \]

output

9058973/1024/(1-2*x)^2-15647317/256/(1-2*x)-24960933/256*x-10989621/256*x^ 
2-631611/32*x^3-235467/32*x^4-147987/80*x^5-3645/16*x^6-23647449/256*ln(1- 
2*x)
 

3.17.31.2 Mathematica [A] (verified)

Time = 0.01 (sec) , antiderivative size = 66, normalized size of antiderivative = 0.90 \[ \int \frac {(2+3 x)^7 (3+5 x)}{(1-2 x)^3} \, dx=-\frac {-52207049+1152760076 x-3056516316 x^2+1218762720 x^3+512613360 x^4+263003328 x^5+113980608 x^6+33219072 x^7+4665600 x^8+472948980 (1-2 x)^2 \log (1-2 x)}{5120 (1-2 x)^2} \]

input

Integrate[((2 + 3*x)^7*(3 + 5*x))/(1 - 2*x)^3,x]
 

output

-1/5120*(-52207049 + 1152760076*x - 3056516316*x^2 + 1218762720*x^3 + 5126 
13360*x^4 + 263003328*x^5 + 113980608*x^6 + 33219072*x^7 + 4665600*x^8 + 4 
72948980*(1 - 2*x)^2*Log[1 - 2*x])/(1 - 2*x)^2
 

3.17.31.3 Rubi [A] (verified)

Time = 0.20 (sec) , antiderivative size = 73, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.100, Rules used = {86, 2009}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {(3 x+2)^7 (5 x+3)}{(1-2 x)^3} \, dx\)

\(\Big \downarrow \) 86

\(\displaystyle \int \left (-\frac {10935 x^5}{8}-\frac {147987 x^4}{16}-\frac {235467 x^3}{8}-\frac {1894833 x^2}{32}-\frac {10989621 x}{128}-\frac {23647449}{128 (2 x-1)}-\frac {15647317}{128 (2 x-1)^2}-\frac {9058973}{256 (2 x-1)^3}-\frac {24960933}{256}\right )dx\)

\(\Big \downarrow \) 2009

\(\displaystyle -\frac {3645 x^6}{16}-\frac {147987 x^5}{80}-\frac {235467 x^4}{32}-\frac {631611 x^3}{32}-\frac {10989621 x^2}{256}-\frac {24960933 x}{256}-\frac {15647317}{256 (1-2 x)}+\frac {9058973}{1024 (1-2 x)^2}-\frac {23647449}{256} \log (1-2 x)\)

input

Int[((2 + 3*x)^7*(3 + 5*x))/(1 - 2*x)^3,x]
 

output

9058973/(1024*(1 - 2*x)^2) - 15647317/(256*(1 - 2*x)) - (24960933*x)/256 - 
 (10989621*x^2)/256 - (631611*x^3)/32 - (235467*x^4)/32 - (147987*x^5)/80 
- (3645*x^6)/16 - (23647449*Log[1 - 2*x])/256
 

3.17.31.3.1 Defintions of rubi rules used

rule 86

Int[((a_.) + (b_.)*(x_))*((c_) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_ 
.), x_] :> Int[ExpandIntegrand[(a + b*x)*(c + d*x)^n*(e + f*x)^p, x], x] /; 
 FreeQ[{a, b, c, d, e, f, n}, x] && ((ILtQ[n, 0] && ILtQ[p, 0]) || EqQ[p, 1 
] || (IGtQ[p, 0] && ( !IntegerQ[n] || LeQ[9*p + 5*(n + 2), 0] || GeQ[n + p 
+ 1, 0] || (GeQ[n + p + 2, 0] && RationalQ[a, b, c, d, e, f]))))
 

rule 2009

Int[u_, x_Symbol] :> Simp[IntSum[u, x], x] /; SumQ[u]
 

3.17.31.4 Maple [A] (verified)

Time = 0.88 (sec) , antiderivative size = 52, normalized size of antiderivative = 0.71

method	result	size
risch	\(-\frac {3645 x^{6}}{16}-\frac {147987 x^{5}}{80}-\frac {235467 x^{4}}{32}-\frac {631611 x^{3}}{32}-\frac {10989621 x^{2}}{256}-\frac {24960933 x}{256}+\frac {\frac {15647317 x}{128}-\frac {53530295}{1024}}{\left (-1+2 x \right )^{2}}-\frac {23647449 \ln \left (-1+2 x \right )}{256}\)	\(52\)
default	\(-\frac {3645 x^{6}}{16}-\frac {147987 x^{5}}{80}-\frac {235467 x^{4}}{32}-\frac {631611 x^{3}}{32}-\frac {10989621 x^{2}}{256}-\frac {24960933 x}{256}-\frac {23647449 \ln \left (-1+2 x \right )}{256}+\frac {15647317}{256 \left (-1+2 x \right )}+\frac {9058973}{1024 \left (-1+2 x \right )^{2}}\)	\(56\)
norman	\(\frac {-\frac {23598297}{128} x +\frac {71192203}{128} x^{2}-\frac {7617267}{32} x^{3}-\frac {6407667}{64} x^{4}-\frac {4109427}{80} x^{5}-\frac {1780947}{80} x^{6}-\frac {64881}{10} x^{7}-\frac {3645}{4} x^{8}}{\left (-1+2 x \right )^{2}}-\frac {23647449 \ln \left (-1+2 x \right )}{256}\)	\(57\)
parallelrisch	\(-\frac {1166400 x^{8}+8304768 x^{7}[phone] x^{6}[phone] x^{5}[phone] x^{4}[phone] \ln \left (x -\frac {1}{2}\right ) x^{2}[phone] x^{3}-472948980 \ln \left (x -\frac {1}{2}\right ) x -711922030 x^{2}[phone] \ln \left (x -\frac {1}{2}\right )[phone] x}{1280 \left (-1+2 x \right )^{2}}\)	\(71\)
meijerg	\(\frac {192 x \left (2-2 x \right )}{\left (1-2 x \right )^{2}}+\frac {2336 x^{2}}{\left (1-2 x \right )^{2}}-\frac {1036 x \left (-18 x +6\right )}{\left (1-2 x \right )^{2}}-\frac {23647449 \ln \left (1-2 x \right )}{256}-\frac {4725 x \left (16 x^{2}-36 x +12\right )}{2 \left (1-2 x \right )^{2}}-\frac {3591 x \left (40 x^{3}+80 x^{2}-180 x +60\right )}{4 \left (1-2 x \right )^{2}}-\frac {14553 x \left (32 x^{4}+40 x^{3}+80 x^{2}-180 x +60\right )}{16 \left (1-2 x \right )^{2}}-\frac {9477 x \left (224 x^{5}+224 x^{4}+280 x^{3}+560 x^{2}-1260 x +420\right )}{128 \left (1-2 x \right )^{2}}-\frac {57591 x \left (512 x^{6}+448 x^{5}+448 x^{4}+560 x^{3}+1120 x^{2}-2520 x +840\right )}{5120 \left (1-2 x \right )^{2}}-\frac {243 x \left (1920 x^{7}+1536 x^{6}+1344 x^{5}+1344 x^{4}+1680 x^{3}+3360 x^{2}-7560 x +2520\right )}{512 \left (1-2 x \right )^{2}}\)	\(247\)

input

int((2+3*x)^7*(3+5*x)/(1-2*x)^3,x,method=_RETURNVERBOSE)
 

output

-3645/16*x^6-147987/80*x^5-235467/32*x^4-631611/32*x^3-10989621/256*x^2-24 
960933/256*x+4*(15647317/512*x-53530295/4096)/(-1+2*x)^2-23647449/256*ln(- 
1+2*x)
 

3.17.31.5 Fricas [A] (verification not implemented)

Time = 0.22 (sec) , antiderivative size = 72, normalized size of antiderivative = 0.99 \[ \int \frac {(2+3 x)^7 (3+5 x)}{(1-2 x)^3} \, dx=-\frac {4665600 \, x^{8} + 33219072 \, x^{7} + 113980608 \, x^{6} + 263003328 \, x^{5} + 512613360 \, x^{4} + 1218762720 \, x^{3} - 1777082220 \, x^{2} + 472948980 \, {\left (4 \, x^{2} - 4 \, x + 1\right )} \log \left (2 \, x - 1\right ) - 126674020 \, x + 267651475}{5120 \, {\left (4 \, x^{2} - 4 \, x + 1\right )}} \]

input

integrate((2+3*x)^7*(3+5*x)/(1-2*x)^3,x, algorithm="fricas")
 

output

-1/5120*(4665600*x^8 + 33219072*x^7 + 113980608*x^6 + 263003328*x^5 + 5126 
13360*x^4 + 1218762720*x^3 - 1777082220*x^2 + 472948980*(4*x^2 - 4*x + 1)* 
log(2*x - 1) - 126674020*x + 267651475)/(4*x^2 - 4*x + 1)
 

3.17.31.6 Sympy [A] (verification not implemented)

Time = 0.07 (sec) , antiderivative size = 65, normalized size of antiderivative = 0.89 \[ \int \frac {(2+3 x)^7 (3+5 x)}{(1-2 x)^3} \, dx=- \frac {3645 x^{6}}{16} - \frac {147987 x^{5}}{80} - \frac {235467 x^{4}}{32} - \frac {631611 x^{3}}{32} - \frac {10989621 x^{2}}{256} - \frac {24960933 x}{256} - \frac {53530295 - 125178536 x}{4096 x^{2} - 4096 x + 1024} - \frac {23647449 \log {\left (2 x - 1 \right )}}{256} \]

input

integrate((2+3*x)**7*(3+5*x)/(1-2*x)**3,x)
 

output

-3645*x**6/16 - 147987*x**5/80 - 235467*x**4/32 - 631611*x**3/32 - 1098962 
1*x**2/256 - 24960933*x/256 - (53530295 - 125178536*x)/(4096*x**2 - 4096*x 
 + 1024) - 23647449*log(2*x - 1)/256
 

3.17.31.7 Maxima [A] (verification not implemented)

Time = 0.20 (sec) , antiderivative size = 56, normalized size of antiderivative = 0.77 \[ \int \frac {(2+3 x)^7 (3+5 x)}{(1-2 x)^3} \, dx=-\frac {3645}{16} \, x^{6} - \frac {147987}{80} \, x^{5} - \frac {235467}{32} \, x^{4} - \frac {631611}{32} \, x^{3} - \frac {10989621}{256} \, x^{2} - \frac {24960933}{256} \, x + \frac {823543 \, {\left (152 \, x - 65\right )}}{1024 \, {\left (4 \, x^{2} - 4 \, x + 1\right )}} - \frac {23647449}{256} \, \log \left (2 \, x - 1\right ) \]

input

integrate((2+3*x)^7*(3+5*x)/(1-2*x)^3,x, algorithm="maxima")
 

output

-3645/16*x^6 - 147987/80*x^5 - 235467/32*x^4 - 631611/32*x^3 - 10989621/25 
6*x^2 - 24960933/256*x + 823543/1024*(152*x - 65)/(4*x^2 - 4*x + 1) - 2364 
7449/256*log(2*x - 1)
 

3.17.31.8 Giac [A] (verification not implemented)

Time = 0.27 (sec) , antiderivative size = 52, normalized size of antiderivative = 0.71 \[ \int \frac {(2+3 x)^7 (3+5 x)}{(1-2 x)^3} \, dx=-\frac {3645}{16} \, x^{6} - \frac {147987}{80} \, x^{5} - \frac {235467}{32} \, x^{4} - \frac {631611}{32} \, x^{3} - \frac {10989621}{256} \, x^{2} - \frac {24960933}{256} \, x + \frac {823543 \, {\left (152 \, x - 65\right )}}{1024 \, {\left (2 \, x - 1\right )}^{2}} - \frac {23647449}{256} \, \log \left ({\left | 2 \, x - 1 \right |}\right ) \]

input

integrate((2+3*x)^7*(3+5*x)/(1-2*x)^3,x, algorithm="giac")
 

output

-3645/16*x^6 - 147987/80*x^5 - 235467/32*x^4 - 631611/32*x^3 - 10989621/25 
6*x^2 - 24960933/256*x + 823543/1024*(152*x - 65)/(2*x - 1)^2 - 23647449/2 
56*log(abs(2*x - 1))
 

3.17.31.9 Mupad [B] (verification not implemented)

Time = 0.04 (sec) , antiderivative size = 51, normalized size of antiderivative = 0.70 \[ \int \frac {(2+3 x)^7 (3+5 x)}{(1-2 x)^3} \, dx=\frac {\frac {15647317\,x}{512}-\frac {53530295}{4096}}{x^2-x+\frac {1}{4}}-\frac {23647449\,\ln \left (x-\frac {1}{2}\right )}{256}-\frac {24960933\,x}{256}-\frac {10989621\,x^2}{256}-\frac {631611\,x^3}{32}-\frac {235467\,x^4}{32}-\frac {147987\,x^5}{80}-\frac {3645\,x^6}{16} \]

input

int(-((3*x + 2)^7*(5*x + 3))/(2*x - 1)^3,x)
 

output

((15647317*x)/512 - 53530295/4096)/(x^2 - x + 1/4) - (23647449*log(x - 1/2 
))/256 - (24960933*x)/256 - (10989621*x^2)/256 - (631611*x^3)/32 - (235467 
*x^4)/32 - (147987*x^5)/80 - (3645*x^6)/16